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A $$CH_3CH_2\underset{Cl}{\underset{|}{C}}H-CH_2\overset{NaNH_2}{\underset{H_2O/\Delta }{\rightarrow }}$$ B $$CH_3CH_2CHBr_2\overset{alc.KOH}{\underset{\Delta }{\rightarrow }}$$ C $$CH_3-\overset{Br}{\overset{|}{\underset{Br}{\underset{|}{C}}}}\overset{Br}{\overset{|}{\underset{Br}{\underset{|}{C}}}}-CH D Potassium maleate $$\overset{electrolysis}{\rightarrow }$$
_3\overset{Zn/alcohol}{\underset{\Delta }{\rightarrow }}$$See AlsoAlkanes, Alkenes, and Alkynes
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Correct option is A. $$CH_3CH_2\underset{Cl}{\underset{|}{C}}H-CH_2\overset{NaNH_2}{\underset{H_2O/\Delta }{\rightarrow }}$$
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